The output of the script would be an error message because the variables $name and $minAge are not defined within the function setAge(). The variables are defined as function parameters, but they are not accessible outside of the function. Additionally, the function setAge() does not have a return statement or any code within the function body to output a result. Therefore, attempting to access the variables $name and $minAge and echo them outside of the function will result in an error.

To fix this issue, you can define the variables $name and $minAge as global variables or pass them as arguments to the function and return them as a result. Here is an example of how the function could be modified to correctly output the values of $name and $minAge:

function setAge ($name, int $minAge = 7) {
global $name, $minAge;
$name = $name;
$minAge = $minAge;
}

setAge(“Fahad”, 30);
echo “The name is $name and the age is $minAge
“;

setAge (“Nourah”, 28);
echo “The name is $name and the age is $minAge
“;

setAge(“Omar”);
echo “The name is $name and the age is $minAge
“;

setAge(“Fatimah”);
echo “The name is $name and the age is $minAge
“;
?>
Alternatively, you could modify the function to return the values of $name and $minAge and then use those returned values to output the result:

function setAge ($name, int $minAge = 7) {
return array($name, $minAge);
}

$result = setAge(“Fahad”, 30);
echo “The name is $result[0] and the age is $result[1]
“;

$result = setAge (“Nourah”, 28);
echo “The name is $result[0] and the age is $result[1]
“;

$result = setAge(“Omar”);
echo “The name is $result[0] and the age is $result[1]
“;

$result = setAge(“Fatimah”);
echo “The name is $result[0] and the age is $result[1]
“;
?>

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